Quadratic Functions

-x²+3x+4=0 <--- This is a Quadratic Function that corresponds to the quadratic formula: ax²+bx+c=0

 1) The first step to graphing a quadratic function you must find the AOS (Axis of Symmetry) the formula for this is    -b/2a

-x²+3x+4=0 your a is the -x² your b is 3x

-3/2(-1)

-3/-2 = 1.5

2) The second step to solving the quadratic formula is by substituting the AOS for your x's in the equation given.

-x²+3x+4=0 becomes -1.5²+3(1.5)+4=0

After the substitution has been done you must solve the equation.

1.5²+3(1.5)+4=0

-2.25+3(1.5)+4=0

-2.25+4.5+4=0

-2.25+8.5=0

 <--- This is what your other point is.

Your vetrex is (1.5,6.25 )

These are your points you get from your AOS and Vertex

Another way to solve this quadratic function is use the quadratic formula: -b±√b² -4ac/2a

You substitute the variables in the original equation into the formula

3±√-3²-4(-1)(4)/2(-1)
3±√9-4(-1)(4)/-2
3±√9+4(4)/-2
3±√9+16/-2
3±√25/-2  <---- You can reduce the √25 to 5
3±5/-2
3+5/-2 or 3-5/-2
-4                1.5
These would be the zeroes or points on the parabola

3 hyperlinks

1)http://www.mathwarehouse.com/quadratic/parabola/interactive-parabola.php
2)http://www.analyzemath.com/Calculators/QuadraticFunctionCal.html
3)http://uncw.edu/courses/mat111hb/pandr/quadratic/quadratic.html#sec1

Five facts about my function:
My function is a positive function, it has a minimum when graphed, the parabola for thte function has been shifted up 2 and over to the left 1.5 from the parent function parabola, the function has an AOS of 1.5, and the vertex is 6.25

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